Physics - Wave Optics Question with Solution | TestHub

According to Brewster's law, the refractive index $\mu$ of a transparent medium is related to the polarising angle $\theta$ by the equation:

$\mu =\tan \theta$

The refractive index is also defined as the ratio of the speed of light in vacuum (or air) to the speed of light in the medium:

$\mu =\frac{C}{V}$

Equating the two expressions for $\mu$, we get:

$\tan \theta =\frac{C}{V}$

Taking the reciprocal of both sides:

$\cot \theta =\frac{V}{C}$

$\theta ={\cot }^{-1}\left(\frac{V}{C}\right)$

Answer: $\theta ={\cot }^{-1}\left(\frac{v}{c}\right)$