In a single-slit diffraction experiment, the slit is illuminated by light of two wavelength λ 1 and λ 2 . It is observed that the 2 nd order diffraction minimum for λ 1 coincides with the 3 rd d

Question

In a single-slit diffraction experiment, the slit is illuminated by light of two wavelength $λ_{1}$ and $λ_{2}$ . It is observed that the 2 nd order diffraction minimum for $λ_{1}$ coincides with the 3 rd diffraction minimum for $λ_{2}$ . Then

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Answer:

C

Solution:

Hint: $d sin θ = n λ$ $n_{1} λ_{1} = n_{2} λ_{2} \frac{λ _{1}}{λ _{2}} = \frac{n _{2}}{n _{1}} = 3/2$

TestHub · Accepted Answer

Hint: d sin θ = n λ ​ n 1 ​ λ 1 ​ = n 2 ​ λ 2 ​ λ 2 ​ λ 1 ​ ​ = n 1 ​ n 2 ​ ​ = 3/2 ​

Physics - Wave Optics Question with Solution | TestHub

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