A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second tourmaline crystal B oriented so that its principal plane is parallel to that of A. The intensity

Question

A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second tourmaline crystal B oriented so that its principal plane is parallel to that of A. The intensity of emergent light is $I_{0}$ . Now $B$ is rotated by $4 5^{\circ}$ about the ray. The emergent light will have intensity $(cos 4 5^{\circ} = \frac{1}{2})$

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Answer:

A

Solution:

Using law of Malus, $I = I_{0} cos^{2} θ = I_{0} (cos^{2} 45) = I_{0} (\frac{1}{2})^{2} = \frac{I _{0}}{2}$

TestHub · Accepted Answer

Using law of Malus, I ​ = I 0 ​ cos 2 θ = I 0 ​ ( cos 2 45 ) = I 0 ​ ( 2 ​ 1 ​ ) 2 = 2 I 0 ​ ​ ​

Physics - Wave Optics Question with Solution | TestHub

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