Physics - Wave Optics Question with Solution | TestHub

Given: Wave length $=\frac{\lambda }{2}$ Path difference of first wave $\Delta x_1=0$ Path difference of second wave $\Delta x_2=\frac{\lambda }{2}$ $\therefore \Delta {\varphi }_1=\frac{2\pi }{\lambda }\cdot \Delta x_1=0$ Similarly, $\Delta {\varphi }_2=\frac{2\pi }{\lambda }\cdot \Delta x_2=\pi$ $\therefore$ Intensity of first wave ${\mathrm{I}}_1=4{\mathrm{I}}_0{\cos }^2(0)=4{\mathrm{I}}_0$ Similarly, Intensity of second wave $I_2=4I_0{\cos }^2\left(\frac{\pi }{2}\right)=0$ $\begin{array}{rl}\therefore & \frac{{\mathrm{I}}_1}{{\mathrm{I}}_2}=\frac{4{\mathrm{I}}_0}{0}=\infty \\ & \Rightarrow \infty :1\end{array}$