Physics - Wave Optics Question with Solution | TestHub

In Young's double slit experiment the intensities at two points, for the path difference $\frac{\lambda }{4}$ and $\frac{\lambda }{3}$ ( $\lambda =$ wavelength of light used) are $I_1$ and $I_2$respectively. If $I_0$ denotes the intensity produced by each one of the individual slits then $\frac{I_1+I_2}{I_0}$ is equal to $\left(\cos 60^{\circ }=0.5,\cos 45^{\circ }=\frac{1}{\sqrt{2}}\right)$