Physics - Wave Optics Question with Solution | TestHub

In Young's double slit experiment, the wavelength of light used is ' $\lambda$ '. The intensity at a point is ' $I$ ' where path difference is $\left(\frac{\lambda }{4}\right)$. If $I_0$ denotes the maximum intensity, then the ratio $\left(\frac{\mathrm{I}}{{\mathrm{I}}_0}\right)$ is $\left(\sin \frac{\pi }{4}=\cos \frac{\pi }{4}=\frac{1}{\sqrt{2}}\right)$