In Young's double Slit experiment, we get 15 fringes per cm on the screen using light of wave length 560 A ˚ . For the same setting how many fringes per cm will be obtained with the light of wavelength 7000 A ˚ ?

X 1 X 2 = λ 2 λ 2 ∴ 15 1 X 2 = 4 5 15 X 2 = 4 5 ∴ X 2 = 12 1 cm ∴ No. off fringes per cm = 12

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2022

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In Young's double Slit experiment, we get 15 fringes per $cm$ on the screen using light of wave length $560 \overset{˚}{A}$ . For the same setting how many fringes per $cm$ will be obtained with the light of wavelength $7000 \overset{˚}{A}$ ?

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Answer:

Solution:

$\frac{X _{2}}{X _{1}} = \frac{λ _{2}}{λ _{2}} ∴ \frac{X _{2}}{\frac{1}{15}} = \frac{5}{4} 15 X_{2} = \frac{5}{4} ∴ X_{2} = \frac{1}{12} cm ∴ No. off fringes per cm = 12$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2022

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