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PhysicsWave OpticsYDSEEasy2 minPYQ_2022
PhysicsEasynumerical

Two beams of light having intensitiesIand4Iinterfere to produce a fringe pattern on a screen. The phase difference between the two beams areπ2andπ3at pointsAandBrespectively. The difference between the resultant intensities at the two points isxI. The value ofxwill be _____ .

Answer:
2.00
Solution:

Given here, phase difference at point A and B are ϕA=π2and ϕB=π3.

Resultant intensity at point A

IA=I+4I+2I4Icosπ2

IA=5I+4I0=5I

Resultant intensity at point B,

IB=I+4I+2I4Icos60° =5I+4I×12=7I

Difference in intensities is IB-IA=7I-5I=2I.

Thus, value of x=2.

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
2mℹ️ Source: PYQ_2022

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