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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minPYQ_2022

PhysicsMediumsingle choice

In Young's double slit experiment with a monochromatic light, maximum intensity is 4 times the minimum intensity in the interference pattern. What is the ratio of the intensities of the two interfering waves?

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Answer:

Solution:

$(I_{1} + I_{2})^{2} = 4 (I_{1} - I_{2})^{2}$ $l_{1} + I_{2} = 2 (l_{1} - I_{2}), 3 I_{2} = I_{1}, \frac{l _{2}}{I _{1}} = \frac{1}{9}$

Stream:WBJEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2022

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