In a Fraunhofer diffraction at a single slit of width d and incident light of wavelength 5500 A , the firs minimum is observed at an angle 3 0 ∘ . The first secondary maxima are observed at an angle θ

Question

In a Fraunhofer diffraction at a single slit of width d and incident light of wavelength 5500 A , the firs minimum is observed at an angle 3 0 ∘ . The first secondary maxima are observed at an angle θ =

TestHub · Accepted Answer

Slit width = d λ = 5500 A ˚ = 5.5 × 1 0 − 7 m , θ 1 ​ = 3 0 ∘ For first secondary minima, d sin θ 1 ​ = λ d = s i n θ 1 ​ λ ​ = s i n 3 0 ∘ 5.5 × 1 0 − 7 ​ = 11 × 1 0 − 7 For first secondary maxima, d sin θ 1 ​ = 2 3 λ ​ ​ ⇒ sin θ 1 ​ = 2 d 3 λ ​ = 2 × 11 × 1 0 − 7 5.5 × 1 0 − 7 ​ = 4 3 ​ θ 1 ​ = sin − 1 ( 4 3 ​ ) ​

Physics - Wave Optics Question with Solution | TestHub

Options:

Doubts & Discussion