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PhysicsWave OpticsYDSEHard2 minPYQ_2021
PhysicsHardsingle choice

In the Young's double slit experiment, the distance between the slits varies in time asdt=d0+a0 sinωt; whered0, ωanda0are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as:

Options:

Answer:
B
Solution:

Fringe width, 

β=λDd

βmaxdmin and βmindmax

d=d0+a0sinωt

dmax=d0+a0 and dmin=d0-a0

 βmin=λDd0+a0 and  βmax=λDd0-a0

βmax-βmin=λDd0-a0-λDd0+a0=2λDa0 d02-a02

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
2mℹ️ Source: PYQ_2021

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