In Fraunhofer diffraction pattern, slit width is 0.2 mm and screen is at 2 m away from the lens. If wavelength of light used is 5000 A ˚ then the distance between the first minimum on either side of the central maximum is ( θ is small and measured in radian)

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PhysicsWave OpticsDiffractionMedium2 minPYQ_2021

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In Fraunhofer diffraction pattern, slit width is $0.2 mm$ and screen is at $2 m$ away from the lens. If wavelength of light used is $5000 \overset{˚}{A}$ then the distance between the first minimum on either side of the central maximum is $(θ$ is small and measured in radian)

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Solution:

Distance between the first minima on either side of the central maximum $= \frac{2 λ D}{a} = \frac{2 \times 5 \times 1 0 ^{- 7} \times 2}{0.2 \times 1 0 ^{- 3}} = 1 0^{- 2} m$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2021

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