Physics - Wave Optics Question with Solution | TestHub

Let$I_0$be the intensity of unpolarised light, so the intensity of first polaroid is$\frac{I_0}{2}.$On rotating through${60}^o$, the intensity of light from second polaroid is

$I=\left(\frac{I_0}{2}\right) {\left(\cos 60\right)}^2$

$=\frac{I_0}{2} \frac{1}{4}=\frac{I_0}{8}=0.125I_0$

So, percentage of incident light transmitted through the system is 12.5%