The sun radiates electromagnetic energy at the rate of 3 .9 × 10 26 W . Its radius is 6.96 × 10 8 m . The intensity of sunlight at the solar surface will be - (in W m - 2 )

I s u r f a c e = P A = 3.9 × 10 26 4 × 3.14 × 6.96 2 × 10 16 =6.4 × 10 7 W m - 2

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The sun radiates electromagnetic energy at the rate of $3 .9 \times 10^{26} W .$ Its radius is $6.96 \times 10^{8} m .$ The intensity of sunlight at the solar surface will be - (in $W m^{- 2}$ )

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Answer:

Solution:

$I_{s u r f a c e} = \frac{P}{A} = \frac{3.9 \times 10^{26}}{4 \times 3.14 \times {(6.96)}^{2} \times 10^{16}}$

$=6.4 \times 10^{7} W m^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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