A Fraunhofer diffraction pattern due to a single slit of width 0 ⋅ 3 mm is obtained on a screen placed at a distance of 3 m from the slit. The first minima lie at 5 ⋅ 5 mm on either side of the centra

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A Fraunhofer diffraction pattern due to a single slit of width 0 ⋅ 3 mm is obtained on a screen placed at a distance of 3 m from the slit. The first minima lie at 5 ⋅ 5 mm on either side of the central maximum on the screen. The wavelength of light used is

TestHub · Accepted Answer

a = 0.3 mm = 0.3 × 1 0 − 3 m , D = 3 m , x = 5.5 mm = 5.5 × 1 0 − 3 m x = a λ D ​ ∴ λ = D xa ​ ∴ 3 λ = 5.5 × 1 0 − 3 × 0.3 × 1 0 − 3 ​ = 5.5 × 1 0 − 7 m = 5500 A ˚

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