Physics - Wave Optics Question with Solution | TestHub

$\lambda =600\mathrm{ n}\mathrm{m}=600\times 10^{-9}m$

$d=0.2\mathrm{ m}\mathrm{m}=0.2\times 10^{-3}m$



$\because$Linear width of central maximum,

$x=\left(2\theta \right)D$

Where,$2\theta :$Angular width of central maximum.

We know that,$x=2\frac{\lambda D}{d}$

Angular width$2\theta .D=2\frac{\lambda D}{d}$

$\Rightarrow 2\theta =\frac{2\lambda }{d}=\frac{2\times 600\times 10^{-9}}{0.2\times 10^{-3}}$

$=6\times 10^{-7}\times 10^4$

$=6\times 10^{-3}\mathrm{ r}\mathrm{a}\mathrm{d}$