In Young's double slit experiment, the light emitted from source has λ = 6.5 × 10 - 7 m and the distance between the two slits is 1 mm. Distance between the screen and slit is 1 metre. Distance b

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In Young's double slit experiment, the light emitted from source has λ = 6.5 × 10 - 7 m and the distance between the two slits is 1 mm. Distance between the screen and slit is 1 metre. Distance between third dark and fifth bright fringe will be

TestHub · Accepted Answer

x 5 = n λ D d = 5 × 6.5 × 10 - 7 × 1 10 - 3 = 32.5 × 10 - 4 m x 3 = 2 n - 1 λ 2 D d = 5 × 6.3 × 10 - 7 × 1 2 × 10 - 3 = 16.25 × 10 - 4 m ∴ x 5 - x 3 ≈ 1.63 m m

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