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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

The intensity of the light coming from one of the slits in YDSE is double the intensity from the other slit. Find the ratio of maximum intensity to minimum intensity in the interference fringe pattern observed.

Options:

Answer:

Solution:

$\frac{I_{max}}{I_{min}} = \frac{{(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}}{{(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2}}$

$N o w I_{1} = 2 I_{2} ⟹ \frac{I_{m a x}}{I_{m i n}} = {(\frac{\sqrt{2 I_{2}} + \sqrt{I_{2}}}{\sqrt{2 I_{2}} - \sqrt{I_{2}}})}^{2}$

${(\frac{\sqrt{2} + 1}{\sqrt{2} - 1})}^{2}$

$= 34$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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