Physics - Wave Optics Question with Solution | TestHub

Resolution limit$=\frac{\text{1.22}\lambda }{\mathit{\text{d}}}$

Again resolution limit$=\text{sin}\theta =\theta =\frac{y}{\mathit{\text{D}}}$

$\therefore$$\frac{y}{\mathit{\text{D}}}=\frac{1·22\lambda }{\mathit{\text{d}}}$



or$\mathit{\text{D}}=\frac{y\mathit{\text{d}}}{\text{1.22}\lambda }$

or$\mathit{\text{D}}=\frac{\left({\text{10}}^{-3}\right)\times \left(3\times {\text{10}}^{-3}\right)}{\left(\text{1.22}\right)\times \left(5\times {\text{10}}^{-7}\right)}=\frac{\text{30}}{\text{6.1}}\approx 5\text{ m}$.