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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

If the ratio of intensities (maximum and minimum) in Young's double slit experiment is 9 : 1, then ratio of amplitude of the coherent sources is

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Answer:

Solution:

According to the question :

$\frac{I_{m a x .}}{I_{m i n .}} = \frac{9}{1} = \frac{{(a_{1} + a_{2})}^{2}}{{(a_{1} - a_{2})}^{2}}$ or $\frac{a_{1} + a_{2}}{a_{1} - a_{2}} = \frac{9}{1}$

$\Rightarrow a_{1} = 2$ and $a_{2} = 1$

$∴ \frac{a_{1}}{a_{2}} = \frac{2}{1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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