Physics - Wave Optics Question with Solution | TestHub

The fringe width in Young’s double-slit experiment

$\mathrm{\beta }=\frac{\mathrm{\lambda D}}{\mathrm{d}}$

where$\lambda$is the wavelength of light used

$\mathrm{D}$ is the distance between slit and screen.

$\mathrm{d}$ is the distance between the slit.

$\therefore \mathrm{\beta }\text{'}=\frac{\mathrm{\lambda }\left(2\mathrm{D}\right)}{\frac{\mathrm{d}}{2}}=4\frac{\mathrm{\lambda D}}{\mathrm{d}}=4\mathrm{\beta }$