A parallel beam of light of wavelength 4000 A ∘ passes through a slit of width 5 × 10 - 3 m . The angular spread of the central maxima in the diffraction pattern is

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Angular spread of the central maxima in the diffraction pattern $= \frac{2 λ}{e}$ ( $e$ = width of the slit)

Here, $e = 5 \times 10^{- 3} m, λ = 4000 Å$

Hence, $2 θ = 2 (\frac{4000 \times 10^{- 10}}{5 \times 10^{- 3}})$

$= 1600 \times 10^{- 7}$ rad

or $2 θ = 1.6 \times 10^{- 4}$ rad

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