Physics - Wave Optics Question with Solution | TestHub

A plane wavefront is incident on a water surface at an angle of incidence $60^{\circ }$ then it gets refracted at $45^{\circ }.$ The ratio of width of incident wavefront to that of refracted wavefront will be $\left[\sin \frac{\pi }{4}=\cos \frac{\pi }{4}=\frac{1}{\sqrt{2}},\sin 60^{\circ }=\frac{\sqrt{3}}{2},\cos 60^{\circ }=\frac{1}{2}\right]$