In Young's experiment for the interference of light, the separation between the slits is d and the distance of the screen from the slits is D . If D is increased by 0.5% and d is decreased by 0.3

Question

In Young's experiment for the interference of light, the separation between the slits is d and the distance of the screen from the slits is D . If D is increased by 0.5% and d is decreased by 0.3% then for the light of a given wavelength, which one of the following is true? "The fringe width.........

TestHub · Accepted Answer

As we know that, fringe width, β = d λ D ​ where, λ = wavelength of light D = Distance of the screen from the slits d = separation between the slits Now, β Δ β ​ × 100 = D Δ D ​ × 100 − d Δ d ​ × 100 According to the question. β Δ β ​ × 100 = 0.5 − ( − 0.3 ) = 0.8% Hence, the fringe width increases by 0.2%

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