Two slits are separated by a distance of 0.5 mm and illuminated with light of λ = 6000 A ˚ . If the screen is placed 2.5 m , from the slits. The distance of the third bright image from the centre will be

Distance of nth bright fringe from the centre, y n = d nD λ ∴ y 3 = 0.5 × 1 0 − 3 3 × 6000 × 1 0 − 10 × 2.5 = 9 × 1 0 − 3 m = 9 mm

Start Free Mock LoginAlready registered? Login here

Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2018

PhysicsEasysingle choice

Two slits are separated by a distance of 0.5 mm and illuminated with light of $λ = 6000 \overset{˚}{A}$ . If the screen is placed 2.5 m , from the slits. The distance of the third bright image from the centre will be

Options:

Answer:

Solution:

Distance of nth bright fringe from the centre, $y_{n} = \frac{nD λ}{d}$ $∴ y_{3} = \frac{3 \times 6000 \times 1 0 ^{- 10} \times 2.5}{0.5 \times 1 0 ^{- 3}} = 9 \times 1 0^{- 3} m = 9 mm$

Stream:JIPMERSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2018

Doubts & Discussion

Loading discussions...