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PhysicsWave OpticsPolarizationMedium2 minPYQ_2018
PhysicsMediumsingle choice

Unpolarized light of intensityIpasses through an ideal polariserA. Another identical polariserBis placed behindA. The intensity of light beyond B is found to beI2. Now another identical polariserCis placed betweenAandB. The intensity beyond B is now found to beI8. The angle between polariserAandCis

Question diagram: Unpolarized light of intensity I passes through an ideal pol

Options:

Answer:
D
Solution:



Transformation axisAandBare parallel. If the transformation axis ofCis making angleθwithA, it will make angle90θwithB. Therefore,

I2cos2θcos2(90θ)=I814sin22θ=14
2θ=π2θ=π4

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:Polarization
2mℹ️ Source: PYQ_2018

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