A single slit of width 0 . 1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0 . 5 m from the slit. The distance of the third dark ban

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A single slit of width 0 . 1 mm is illuminated by a parallel beam of light of wavelength 6000 Å and diffraction bands are observed on a screen 0 . 5 m from the slit. The distance of the third dark band from the central bright band is:

TestHub · Accepted Answer

a = 0.1 mm = 10 - 4 m λ = 6000 × 10 - 10 = 6 × 10 - 7 m D = 0.5 m For 3 r d dark a sin ⁡ θ = 3 λ sin ⁡ θ = 3 λ a = x D x = 3 λ D a = 3 × 6 × 10 - 7 × 0.5 10 - 4 = 9 mm

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