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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2016

PhysicsEasysingle choice

When a plastic thin film of refractive index $1.45$ is placed in the path of one of the interfering waves then the central fringe is displaced through width of five fringes. The thickness of the film, if the wavelength of light is $5890 \overset{˚}{A}$ , will be

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Solution:

$X_{0} = \frac{β}{λ} (μ - 1) t \Rightarrow 5 β = \frac{β ( 0.45 ) t}{5890 \times 1 0 ^{- 10}}$ $∴ t = \frac{5 \times 5890 \times 1 0 ^{- 10}}{0.45} = 6.544 \times 1 0^{- 4} cm$

Stream:VITEEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2016

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