In Young's double-slit experiment, the distance between slits and the screen is 1 m and monochromatic light of wavelength 600 nm is being used. A person standing near the slits is looking at the

Question

In Young's double-slit experiment, the distance between slits and the screen is 1 m and monochromatic light of wavelength 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d 0 between the slits. If the angular resolution of the eye is 1 60 ° , then the value of d 0 is close to

TestHub · Accepted Answer

When the angular fringe width in the interference pattern becomes less than the angular resolving power of the person's eye, the fringes will disappear.

The angular fringe width $θ_{0} = \frac{β}{D} = \frac{λ}{d_{0}}$

$d_{0} = \frac{λ}{θ_{0}} = \frac{600 \times 10^{- 9}}{(\frac{1}{60} \times \frac{π}{180})}$

$d_{0} = \frac{600 \times 60 \times 180 \times 10^{- 9}}{π} m = 2 mm$

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