Physics - Wave Optics Question with Solution | TestHub

$\beta =\frac{\lambda \text{D}}{\text{d}\text{.}}$

$\therefore {\beta }^1=\frac{\lambda 2\text{D}}{\text{d.}}$

Now shift$=\frac{\left(\mu -1\right)\text{t D}}{\text{d}}$

$\mathrm{y}={\beta }^1$

$\frac{\left(\mu -1\right)\text{t D}}{\text{d}}=\frac{\lambda \text{.}2\text{D}}{\text{d}}$

$\lambda =\frac{\left(\mu -1\right)\text{t}}{2}=\frac{\left(\text{1.6}-1\right)\times \text{1.8}}{2}$

$=\frac{\text{0.6}\times \text{1.8}}{2}\mu \text{m}$

$=\text{0.3}\times \text{1.8}\mathrm{ \mu }\text{m}$

$=\text{0.54}\mathrm{ \mu }\text{m}$

= 540 nm