In Young’s double-slit experiment, the distance between the two identical slits is 6 . 1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of th

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In Young’s double-slit experiment, the distance between the two identical slits is 6 . 1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single-slit diffraction pattern is :

TestHub · Accepted Answer

d = separation between 2 slits a = slit width β y = fringe width in YDSE & β D = width of central maxima β y = λ D d = λ D 6.1 a β D = 2 λ D a β D = 2 × 6.1 β y = 12.2 β y

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