Physics - Wave Optics Question with Solution | TestHub

We know that The maximum intensities $$I_{\max }={\left(\sqrt{I_1}+\sqrt{I_2}\right)}^2$$ The minimum intensities $$I_{\min }={\left(\sqrt{I_1}-\sqrt{I_2}\right)}^2$$ So, the ratio of the maximum and minimum of intensities is $$\begin{array}{rl}\frac{I_{\max }}{I_{\min }}& =\frac{{\left(\sqrt{I_1}+\sqrt{I_2}\right)}^2}{{\left(\sqrt{I_1}-\sqrt{I_2}\right)}^2}\\ \frac{I_{\max }}{I_{\min }}& =\frac{(\sqrt{4I}+\sqrt{I}{)}^2}{(\sqrt{4I}-\sqrt{I}{)}^2}\\ & ={\left(\frac{3\sqrt{I}}{\sqrt{I}}\right)}^2\\ =& \frac{9}{1}=9:1\end{array}$$