The first diffraction minimum due to the single slit diffraction is seen at θ = 3 0 ∘ for a light of wavelength 5000 A ˚ falling perpendicularly on the slit. The width of the slit is

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For first minimum, d sin θ = λ ⇒ d ​ = sin θ λ ​ = sin 3 0 ∘ 5000 × 1 0 − 8 cm ​ = 1/2 5000 × 1 0 − 8 cm ​ = 10 × 1 0 − 5 cm ​

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