In a Young's double slit experiment, the fringe width is found to be 2 mm , when light of wavelength 6000 A ˚ is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index 1.33.

Fringe width β = 2 mm = 2 × 1 0 − 3 m λ μ β ′ β ′ = 6000 A ˚ = 1.33 = ? = μ β = 1.33 2 = 1.5 mm

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minPYQ_2010

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In a Young's double slit experiment, the fringe width is found to be $2 mm$ , when light of wavelength $6000 \overset{˚}{A}$ is used. Find the change in fringe width if the whole apparatus is immersed in water of refractive index $1.33.$

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Solution:

Fringe width $β = 2 mm = 2 \times 1 0^{- 3} m$ $λ μ β^{'} β^{'} = 6000 \overset{˚}{A} = 1.33 = ? = \frac{β}{μ} = \frac{2}{1.33} = 1.5 mm$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2010

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