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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2009

PhysicsEasysingle choice

In an interference experiment, third bright fringe is obtained at a point on the screen with a light of $700 nm$ . What should be the wavelength of the light source in order to obtain 5 th bright fringe at the same point?

Options:

Answer:

Solution:

$n_{1} λ_{1} = n_{2} λ_{2}$ $\Rightarrow 3 \times 700 = 5 \times λ_{2}$ $\Rightarrow λ_{2} = 420 nm$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2009

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