Standing waves are produced by superposition of two waves y 1 = 0.05 sin ( 3 π t − 2 x ) and y 2 = 0.05 sin ( 3 π t + 2 x ) , where x and y are measured in metre and t in second. Find the amplitud

Question

Standing waves are produced by superposition of two waves $y_{1} = 0.05 sin (3 π t - 2 x)$ and $y_{2} = 0.05 sin (3 π t + 2 x)$ , where $x$ and $y$ are measured in metre and $t$ in second. Find the amplitude of the particle at $x = 0.5$ m.

Answer:

0.05

Solution:

$y = 0.1 sin 3 π t cos 2 x$ . At $x = 0.5$ : amplitude = $0.1 cos (1 rad) = 0.1 \times 0.540 = 0.054$ m.

TestHub · Accepted Answer

y = 0.1 sin 3 π t cos 2 x . At x = 0.5 : amplitude = 0.1 cos ( 1 rad ) = 0.1 × 0.540 = 0.054 m.

Physics - Wave on String Question with Solution | TestHub

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