A pulse is y = 1 + x 2 1 at t = 0 and y = 1 + ( x − 2 ) 2 1 at t = 1 s, with the shape unchanged. Find the wave speed. (answer in m/s ).

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PhysicsWave on StringWavesHard2 minQB

PhysicsHardinteger

A pulse is $y = \frac{1}{1 + x ^{2}}$ at $t = 0$ and $y = \frac{1}{1 + ( x - 2 ) ^{2}}$ at $t = 1$ s, with the shape unchanged. Find the wave speed. (answer in $m/s$ ).

Answer:

Solution:

The peak moves from $x = 0$ to $x = 2$ m in 1 s, so $v = 2$ m/s.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

⏱ 2mℹ️ Source: QB

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