The equation of displacement of two waves are given as y 1 = 10 sin ( 3 π t + 3 π ) ; y 2 = 5 ( sin 3 π t + 3 cos 3 π t ) . Then what is the ratio of their amplitudes:

y 2 = 5 ⋅ 2 ( 2 1 sin 3 π t + 2 3 cos 3 π t ) = 10 sin ( 3 π t + π /3 ) . Amplitude 10 for both, so 1 : 1.

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The equation of displacement of two waves are given as $y_{1} = 10 sin (3 π t + \frac{π}{3})$ ; $y_{2} = 5 (sin 3 π t + 3 cos 3 π t)$ . Then what is the ratio of their amplitudes:

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Answer:

Solution:

$y_{2} = 5 \cdot 2 (\frac{1}{2} sin 3 π t + \frac{3}{2} cos 3 π t) = 10 sin (3 π t + π /3)$ . Amplitude 10 for both, so 1 : 1.

Stream:JEESubject:PhysicsTopic:Wave on StringSubtopic:Waves

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