Physics - Wave on String Question with Solution | TestHub

Given frequency $f=500$ Hz and velocity $v=300$ m/s.

The wavelength $\lambda$ is given by:

$\lambda =\frac{v}{f}=\frac{300}{500}=0.6$ m

The phase difference $\Delta \varphi$ is related to the path difference $\Delta x$ by the formula:

$\Delta \varphi =\frac{2\pi }{\lambda }\Delta x$

Given $\Delta \varphi =60^{\circ }=\frac{\pi }{3}$ radians, we have:

$\frac{\pi }{3}=\frac{2\pi }{0.6}\Delta x$

$\Delta x=\frac{0.6}{6}=0.1$ m

The minimum distance between the two points is $0.1$ m.

Answer: $0.1$ m