Physics - Wave on String Question with Solution | TestHub

Given:
Amplitude $A=1$ m
Wavelength $\lambda =2\pi$ m
Frequency $f=\frac{1}{\pi }$ Hz

The wave number $k$ is calculated as:
$k=\frac{2\pi }{\lambda }=\frac{2\pi }{2\pi }=1$ m${}^{-1}$

The angular frequency $\omega$ is calculated as:
$\omega =2\pi f=2\pi \left(\frac{1}{\pi }\right)=2$ rad/s

The standard equation of a wave travelling in the positive $x$-direction is given by:
$y=A\sin (kx-\omega t)$

Substituting the values of $A$, $k$, and $\omega$, we get:
$y=1\sin (1\cdot x-2\cdot t)$
$y=\sin (x-2t)$

Answer: $y=\sin (x-2t)$