Physics - Wave on String Question with Solution | TestHub

Given frequency $f=400\text{ Hz}$ and velocity $v=336\text{ m/s}$.

The wavelength $\lambda$ is given by:

$\lambda =\frac{v}{f}=\frac{336}{400}=0.84\text{ m}$

The phase difference is given as $\Delta \varphi =60^{\circ }=\frac{\pi }{3}\text{ rad}$.

The relation between phase difference $\Delta \varphi$ and path difference $\Delta x$ is:

$\Delta \varphi =\frac{2\pi }{\lambda }\Delta x$

Substituting the values:

$\frac{\pi }{3}=\frac{2\pi }{0.84}\Delta x$

$\Delta x=\frac{0.84}{6}=0.14\text{ m}$

Answer: 0.14 m