Prong of a vibrating tuning fork is in contact with water surface. It produces concentric circular waves on the surface of water. The distance between five consecutive crests is 0.8 m and the velocity

Question

Prong of a vibrating tuning fork is in contact with water surface. It produces concentric circular waves on the surface of water. The distance between five consecutive crests is 0.8 m and the velocity of wave on the water surface is 56 m / s . The frequency of tuning fork is

TestHub · Accepted Answer

The distance between five consecutive crests corresponds to $4 λ$ .

$4 λ = 0.8 m$

$λ = 0.2 m$

The velocity of the wave is given as $v = 56 m/s$ .

Using the relation $v = f λ$ , the frequency $f$ is:

$f = \frac{v}{λ}$

$f = \frac{56}{0.2} = 280 Hz$

Answer: 280 Hz

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