41 tuning forks are arranged in increasing order of frequency such that each produces 5 beats/second with next tuning fork. If frequency of last tuning fork is double that of frequency of first fork.

Question

41 tuning forks are arranged in increasing order of frequency such that each produces 5 beats/second with next tuning fork. If frequency of last tuning fork is double that of frequency of first fork. Then frequency of first and last fork is

TestHub · Accepted Answer

Let Frequency of 1 st tuning fork be = n 1 ​ ∴ frequency of 4 1 st tuning fork = n 41 ​ Now, ∴ ∴ ∴ ​ n 41 ​ = n 1 ​ + ( 41 − 1 ) × 5 But, n 41 ​ = 2 n 1 ​ 2 n 1 ​ = n 1 ​ + 200 n 1 ​ = 200 Hz n 41 ​ = 400 Hz ​

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