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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringMiscellaneousMedium2 minPYQ_2022

PhysicsMediumsingle choice

A string in a musical instrument is $50 cm$ long and its fundamental frequency is $800 Hz$ . Keeping the tension applied to the string same, the change in the length to produce sound note of fundamental frequency $1000 Hz$ will be.

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Answer:

Solution:

For stretched string $v \propto \frac{1}{l}$ $∴ \frac{v _{1}}{v _{2}} = \frac{l _{2}}{l _{1}} \Rightarrow l_{2} = \frac{800}{1000} \times 50 = 40 cm$

Stream:MHT_CETSubject:PhysicsTopic:Wave on StringSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2022

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