Two waves are represented by the equation, y 1 = A sin ( ω t + kx + 0.57 ) m and y 2 = A cos ( ω t + kx ) m , where x is in metre and t is in second. What is the phase difference between them?

Question

Two waves are represented by the equation, y 1 ​ = A sin ( ω t + kx + 0.57 ) m and y 2 ​ = A cos ( ω t + kx ) m , where x is in metre and t is in second. What is the phase difference between them?

TestHub · Accepted Answer

​ y 1 ​ = A sin ( ω t + kx + 0.57 ) y 2 ​ = A cos ( ω t + kx ) = A sin ( ω t + kx + 2 π ​ ) ∴ Phase difference = 2 π ​ − 0.57 = 2 3.14 ​ − 0.57 = 1.57 − 0.57 = 1.0 rad ​

Physics - Wave on String Question with Solution | TestHub

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