A metal wire of linear mass density of 9.8 g m - 1 is stretched with a tension of 10 kg - wt between two rigid supports 1 m apart. The wire passes at its middle point between the poles of a permanent

Question

A metal wire of linear mass density of 9.8 g m - 1 is stretched with a tension of 10 kg - wt between two rigid supports 1 m apart. The wire passes at its middle point between the poles of a permanent magnet and it vibrates in resonance when carrying an alternating current of frequency n . The frequency n of the alternating sources is

TestHub · Accepted Answer

The wire will vibrate with the same frequency as that of the source. This can be considered as an example of forced vibration.

$T = 10 \times 9.8 N = 98 N$

$m = 9.8 \times 10^{- 3} k g m^{- 1}$

Frequency of wire

$n = \frac{1}{2 L} \sqrt{(\frac{T}{m})}$

$= \frac{1}{2 \times 1} \sqrt{(\frac{98}{9.8 \times 10^{- 3}})} = 50 H z$

Physics - Wave on String Question with Solution | TestHub

Options:

Doubts & Discussion