A 20 cm long string, having a mass of 1.0 g , is fixed at both the ends. The tension in the string is 0.5 N . The string is set into vibrations using an external vibrator of frequency 100 Hz . Find th

Question

A 20 cm long string, having a mass of 1.0 g , is fixed at both the ends. The tension in the string is 0.5 N . The string is set into vibrations using an external vibrator of frequency 100 Hz . Find the separation (in cm ) between the successive nodes on the string.

TestHub · Accepted Answer

l = 20 cm ; m = 1 g ; T = 0 .5 N ; f = 100 Hz μ = 1 × 10 - 3 20 × 10 - 2 = 1 2 × 10 - 2 V = 0.5 0.5 × 10 - 2 = 10 m s - 1 m/s λ = 0.1 λ 2 = 0.05 m = 5 c m

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