Physics - Wave on String Question with Solution | TestHub

Here,$\text{T = 80}$kgf =$\text{= 80 }\times \text{ 9}\text{.8 }$N ;

$\text{m = 6}{\text{.4 × 10}}^{-3}$kg m^-1

$Now,\upsilon =\sqrt{\frac{\text{T}}{\text{m}}}=\sqrt{\frac{80\times 9·8}{6·4\times 10^{-3}}}=350\text{m }{\text{s}}^{-1}$

Therefore, time taken by the wave pulse to traverse 0.7 m length of the string,

$t=\frac{l}{\upsilon }=\frac{\text{0}\text{.}7}{350}=2\times 10^{-3 }$s