Physics - Wave on String Question with Solution | TestHub

The frequency of sonometer wire is

$v=\frac{1}{2l}\sqrt{\frac{T}{m}}$

Taking logarithm and differentiating, we get

$\frac{∆v}{v}=\frac{∆l}{l}+\frac{1}{2}\frac{∆T}{T}+\frac{1}{2}\frac{∆m}{m}$

$\therefore \frac{∆v}{v}=\frac{∆l}{l}=1\%$

Hence, frequency will increase by 1%