If frequency ( v ) of light is 5 × 1 0 16 Hz and speed of light in air is 3 × 1 0 8 m / s . Find the ratio of wavelength of light in a medium of refractive index ' 2 ' to air

v = v λ , Here, v is same as source of light. ⇒ v ∝ λ , v 2 v 1 = λ 2 λ 1 But v 1 = n 1 c , v 2 (in air) = n 2 c = c ⇒ λ 2 λ 1 = c c / n 1 = n 1 1 = 2 1 ⇒ n 1 = 2

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Physics - Wave on String Question with Solution | TestHub

PhysicsWave on StringEquation/graphEasy2 minPYQ_2019

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If frequency $(v)$ of light is $5 \times 1 0^{16} Hz$ and speed of light in air is $3 \times 1 0^{8} m / s$ . Find the ratio of wavelength of light in a medium of refractive index ' 2 ' to air

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Solution:

$v = v λ$ , Here, $v$ is same as source of light. $\Rightarrow v \propto λ, \frac{v _{1}}{v _{2}} = \frac{λ _{1}}{λ _{2}} But v_{1} = \frac{c}{n _{1}}, v_{2} (in air) = \frac{c}{n _{2}} = c \Rightarrow \frac{λ _{1}}{λ _{2}} = \frac{c / n _{1}}{c} = \frac{1}{n _{1}} = \frac{1}{2} \Rightarrow n_{1} = 2$

Stream:JIPMERSubject:PhysicsTopic:Wave on StringSubtopic:Equation/graph

⏱ 2mℹ️ Source: PYQ_2019

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